x^2+1.3x-58500=0

Solution for x^2+1.3x-58500=0 equation:

x^2+1.3x-58500=0

a = 1; b = 1.3; c = -58500;
Δ = b2-4ac
Δ = 1.32-4·1·(-58500)
Δ = 234001.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.3)-\sqrt{234001.69}}{2*1}=\frac{-1.3-\sqrt{234001.69}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.3)+\sqrt{234001.69}}{2*1}=\frac{-1.3+\sqrt{234001.69}}{2}
$